There is a uniform electrostatic field in a r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In a uniform electric field $\vec{E}$,the potential $V$ at a position $\vec{r}$ relative to point $P$ is given by $V = V_P - \vec{E} \cdot \vec{r}

Vedclass · Accepted Answer

$589.2$

Vedclass · Answer

(B) In a uniform electric field $\vec{E}$,the potential $V$ at a position $\vec{r}$ relative to point $P$ is given by $V = V_P - \vec{E} \cdot \vec{r} = V_P - Er \cos 	heta$,where $	heta$ is the angle between the radius vector and the field direction.The potential varies between $V_{min} = V_P - Er$ (at $	heta = 0^o$) and $V_{max} = V_P + Er$ (at $	heta = 180^o$).Given $V_{min} = 589.0\,V$ and $V_{max} = 589.8\,V$,the potential difference across the diameter is $2Er = 589.8 - 589.0 = 0.8\,V$. Thus,$Er = 0.4\,V$.The center potential $V_P$ is the average: $V_P = (589.0 + 589.8) / 2 = 589.4\,V$.For a point at an angle $	heta = 60^o$,the potential is $V = V_P - Er \cos(60^o) = 589.4 - 0.4 	imes 0.5 = 589.4 - 0.2 = 589.2\,V$.

Similar Questions

Two charges $+q$ and $-q$ are placed at points $A$ and $B$ respectively, which are at a distance $2L$ apart. $C$ is the midpoint of $A$ and $B$. The work done in moving a charge $+Q$ along the semicircle $CSD$ $(W_1)$ and along the line $CBD$ $(W_2)$ are:

$A$ cube of side $b$ has a charge $q$ at each of its vertices. Determine the potential and electric field due to this charge array at the centre of the cube.

$A$ conductor with a positive charge:

$A$ charge of $10^{-3} \ \mu C$ is placed at the origin $(0, 0)$ of an $X-Y$ coordinate system. Two points $A$ and $B$ are located at $(\sqrt{2}, \sqrt{2})$ and $(2, 0)$ respectively. The potential difference between points $A$ and $B$ is ....... $V$.

The potential of a large liquid drop formed when eight identical small liquid drops are combined is $20 \,V$. What was the potential of each single small drop (in $\,V$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module